C指针问题

char c[3]; //Creates an array of 3 bytes - the first 2 bytes can be used for characters and the 3rd would need to be used for the terminating zero

*c = 'a'; //sets c[0] to 'a'
*c++; //moves the pointer to c[1]
*c = 'b'; //sets c[1] to 'b'
*c++; //moves the pointer to c[2]
*c = '\0' //sets c[2] to the terminating zero

首先,这里的c不是指针,它是一个数组.在某些情况下,数组可以像指针一样使用,但它们不是同一个东西.特别是,您可以使用* c(就好像它是一个指针)来访问第一个位置的值,但由于c实际上不是指针,因此您无法使用c更改c指向的位置.

其次,你误解了*的意思.它不仅仅是使用指针时使用的装饰.作为运算符,它意味着“取消引用”,即让我访问所指向的内容.因此,当您操作指针本身(例如,通过递增它)而不操纵指向的数据时,您不需要使用它.

这是你可能想要的：

char c[3]; // Creates an array of 3 bytes - the first 2 bytes can be used for characters 
           // and the 3rd would need to be used for the terminating zero
char* p_c; // Creates a character pointer that we will use to refer into the c array

p_c = &c[0]; // Assign the address of the first element of the c array to the p_c pointer.
             // This Could also be "p_c = c",taking advantage of the fact that in this
             // is one of the circumstances in which an array can be treated as if it were 
             // a pointer to its first element

*p_c = 'a'; //sets c[0] to 'a'
p_c++;      //moves the pointer to c[1] (note no *)
*p_c = 'b'; //sets c[1] to 'b'
p_c++;      //moves the pointer to c[2] (note no *)
*p_c = '\0' //sets c[2] to the terminating zero