objective-c – Swift中的块显示错误“调用中缺少参数#2的参数”

我现在在我的项目中使用Jonas Gessner的 JGActionSheet与Swift,并且示例是由Objective-C编写的,当我尝试将块转换为Swift时,Xcode显示错误“在调用中缺少参数#2的参数”,这里是我写的代码和截图：

Objective-C样本

JGActionSheet *sheet = [JGActionSheet actionSheetWithSections:sections];
[sheet setButtonPressedBlock:^(JGActionSheet *sheet,NSIndexPath *indexPath) 
{
    [sheet dismissAnimated:YES];
}];@H_944_10@ 
 
我用Swift编写的代码
 
 
 
 
let actionSheet = JGActionSheet(sections: sections)
actionSheet.buttonPressedBlock {
    (sheet: JGActionSheet!,indexPath: NSIndexPath!) in
    actionSheet.dismissAnimated(true)
}@H_944_10@ 
 
错误截图
 
 
Missing argument for parameter #2 in call
 
 
所以请帮我解决这个问题,非常感谢！

myThing.myProperty = myValue@H_944_10@ 
 
您尝试将此属性设置为块(函数)的事实不会改变任何内容.所以：
 
 
 
 
let actionSheet = JGActionSheet(sections: sections)
actionSheet.buttonPressedBlock = {
    (sheet: JGActionSheet!,indexPath: NSIndexPath!) in
    actionSheet.dismissAnimated(true)
}@H_944_10@