没有clang警告或错误,如果C 11 lambda返回错误类型

参见英文答案 > Using `std::function<void(…)>` to call non-void function                                    3个
看起来我的clang编译器(3.3)不会产生任何错误,如果lambda的返回类型不匹配：

#include <functional>
typedef std::function<void()> voidFunc;

void foo(voidFunc funC) 
{
    func();
}

int main() 
{
    int i = 42;
    foo([i]()
    {
        return i;
    });
    return 0;
}

编译此代码不会显示任何错误：

clang++ -c -Xclang -stdlib=libc++ -std=c++11 -Weverything -Wno-c++98-compat -Wno-missing-prototypes -o foo.o foo.cpp

如何为此类问题生成类型错误？

编辑：

这会生成类型错误：

#include <functional>

struct A {};
struct B {};

typedef std::function<A()> aFunc;

void foo(aFunc funC)
{
    func();
}

int main()
{
    int i = 42;
    foo([i]() 
    {
        return B();
    });
    return 0;
}

这是错误：

foo2.cpp:16:2: error: no matching function for call to 'foo'
        foo([i]() {
        ^~~
foo2.cpp:8:6: note: candidate function not viable: no kNown conversion from '<lambda at foo2.cpp:16:6>' to 'aFunc' (aka 'function<A ()>') for 1st argument
void foo(aFunc funC)
     ^
1 error generated.

void f(A const&);
f(the_lambda()); // nope!

long f(doublE);

double d;
int i;

long a = f(d);  // call signature is long(doublE)
                // called with double,returning into a long
short b = f(i); // call signature is short(int)
                // called with int,returning into a short