C预处理器为生成的函数名定义

void CallBACk_SignalName1(void);
void CallBACk_SignalName2(void);
...etc

#define SIGNAL1 SignalName1
#define SIGNAL2 SignalName2

#define Function_name(signal) (void  CallBACk_ ## signal ## (void))
...
...
Function_name(SIGNAL1)
{
  ..
  return;
}

void CallBACk_SIGNAL1(void)

void CallBACk_SignalName1(void)

解决方法@H_197_22@

您需要提供额外级别的“类似功能的宏”,以确保正确扩展：

例如

#define SIGNAL1 SignalName1
#define SIGNAL2 SignalName2

#define MAKE_FN_NAME(X) void  CallBACk_ ## x (void)
#define Function_name(signal) MAKE_FN_NAME(signal)

Function_name(SIGNAL1)
{
    return;
}

输出：

$gcc -E prepro.cc 
# 1 "prepro.cc"
# 1 "<built-in>"
# 1 "<command-line>"
# 1 "prepro.cc"







void CallBACk_SignalName1 (void)
{
 return;
}