程序集 – MZ(DOS,16位).EXE标头中页面计数和最后一页大小的重要性

作为极端情况,即使设置1个1字节的页面,以下程序也会起作用：

;
; the smallest possible "Hello,World!" .EXE (DOS Mz) file
; assemble with:
; nasm -f bin -w+all -O0 smallest_Hello_exe.asm -o ASm.EXE
;

bits 16
cpu 8086

;
; by setTing cs:ip=-10h:100h instead of 0h:0h inside the .EXE header
; (identical assignments),we achieve the following two advantages:
; 1) ds==cs,so no "push cs pop ds" is needed in order for ds:dx
; to point to the message String
; 2) we can exit by int 20h instead of int 21h,thus omitTing the
; ah=4ch assignment
; (int 20h requires that cs points to the PSP segment)
;

;
; we do not the address calculations to take the .EXE header into account
; so we must subtract its length (20h) by an "org -20h"
; but,since ip will be 100h,we must also issue an "org 100h"
; and,since 0x100-0x20=0xE0...

org 0xE0        ; 100h for ip value - 20h for header



section .text align=1
;
; the MZ .EXE header structure
; 28 bytes long
; 1 pararaph equals 16 bytes
; 1 page equals 512 bytes
; suggested reading: int 21h,ah=4bh procedure
;
host_exe_header:
.signature: dw 'MZ'     ; the 'MZ' characters
.last_page_size: dw 1   ; number of used bytes in the final file page,0 for all
.page_count: dw 1       ; number of file pages including any last partial page
.reloc: dw 0            ; number of reLOCATIOn entries after the header
.paragraphs: dw 2       ; size of header + reLOCATIOn table,in paragraphs
.minalloc: dw 0         ; minimum required additional memory,in paragraphs
.maxalloc: dw 0xFFFF    ; maximum memory to be allocated,in paragraphs
.in_ss: dw 0            ; initial relative value of the stack segment
.in_sp: dw 0xF000       ; initial sp value
.checksum: dw 0         ; checksum: 1's complement of sum of all words
.in_ip: dw 100h         ; initial ip value
.in_cs: dw -10h         ; initial relative value of the text segment
.offset: dw 0           ; offset of the reLOCATIOn table from start of header
.overlay: dw 0          ; overlay value (0h = main program)

; pad header (its size in bytes must be a multiple of 16)
times (32-$+$$) db 0

mov dx,message
mov ah,09h              ; write String ds:dx to stdout
int 21h
int 20h

section .data align=1
message: db 'Hello,World!$'

section .bss align=1

尝试不同的程序大小,我得出结论,Dos将每页的所有512字节加载到内存中.如果是这样,最后一页中字节数的目的是什么？

它会干扰.bss,堆栈数据和/或动态内存分配吗？