将uint8_t数组复制到结构

uint8_t *buffer = "JOHN:DOE:010119:M:FOO:BAR";

我想逐字段地将它复制到数据结构中

typedef struct{
  uint8_t firstName[5];
  uint8_t pad1;
  uint8_t lastName[4];
  uint8_t pad2;
  uint8_t dateOfBirth[7];
  uint8_t pad3;
  uint8_t genre;
  uint8_t pad4;
  uint8_t car[4];
  uint8_t pad5;
  uint8_t phone[4];
  uint8_t pad6;
}DataStructTypeDef;

假设所有长度都是固定的(例如,firstName总是由4个字符组成,lastName为3等…)

我用这种方法：

DataStructTypeDef foo;
memcpy((void *)&foo,(void *)buffer,sizeof(DataStructTypeDef));

当我尝试打印dateOfBirth时,它会显示从01012019开始的整个数组

int main(void)
{
  DataStructTypeDef foo;
  memcpy((void *)&foo,sizeof(DataStructTypeDef));
  printf("%s",foo.dateOfBirth); // It prints 010119:M:FOO:BAR
//printf("%s",foo.dateOfBirth); // Expected value 010119
  return 0;
}