swift – 在super.init中引用self

import UIKit

struct Action
{
    let text: String
    let handler: (() -> Void)?
}

class AlertView : UIView
{
    init(actions: [Action]) {
        super.init(frame: .zero)

        for action in actions {
//            let actionButton = ActionButton(type: .custom)
//            actionButton.title = action.title
//            actionButton.handler = action.handler
//            addSubview(actionButton)
        }
    }

    required init?(coder aDecoder: NSCoder) {
        fatalError("init(coder:) has not been implemented")
    }
}

class TextAlertView : AlertView
{
    init() {
        super.init(actions: [
            Action(text: "No",handler: nil),Action(text: "Yes",handler: { [weak self] in
                //use self in here..
            })
        ])
    }

    required init?(coder aDecoder: NSCoder) {
        fatalError("init(coder:) has not been implemented")
    }
}

class MyViewController : UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad()

        let alert = TextAlertView()
        view.addSubview(alert)
        self.view = view
    }
}@H_772_8@ 
 
每次我实例化TextAlertView时,它都会在访问不良的super.init上崩溃.但是,如果我改变：
 
 
 
 
Action(title: "Yes",{ [weak self] in
    //use self in here..
})@H_772_8@ 
 
至：
 
 
 
 
Action(title: "Yes",{
    //Blank.. doesn't reference `self` in any way (weak,uNowned,etC)
})@H_772_8@ 
 
有用！
 
 
在超级初始化期间有没有办法在动作块中引用自身弱或不弱(在上面我在super.init的参数中做它？
 
 
代码编译..它只是在运行时随机崩溃.