swift3 – 使用带多个参数的选择器的Swift 4

参见英文答案 > Passing arguments to selector in Swift@R_874_5179@@R_874_5179@@R_874_5179@@R_874_5179@@R_874_5179@ 2个 @H_616_5@>@R_874_5179@      Attach parameter to button.addTarget action in Swift@R_874_5179@@R_874_5179@@R_874_5179@@R_874_5179@@R_874_5179@ 10个 @H_616_5@我用Swift 4编写并尝试编写一个函数,将categoryId作为动作发送但我无法写.我认为我的语法是错误的.如果我编写没有参数的函数它不是问题,但我得到参数函数的错误.你能说我怎么用选择器吗？

@objc func sendCategoryIdToPackageSELEctionVC(categoryId : int){
        MarketVC.categoryId = categoryId
        self.performSegue(withIdentifier: "sequeGoToPackageSELEction",sender: nil)
    }

func addTapFeatures(){
        taplabel1 = UITapGestureRecognizer(target: self,action: #SELEctor(self.sendCategoryIdToPackageSELEctionVC(categoryId:2)))
        taplabel1?.cancelsTouchesInView = false
        self.labelFirst.addGestureRecognizer(taplabel1!)
}

我收到一个错误,说操作选择器没有引用任何objc方法.

@objc func someMethod() { // name this properly!
    handleTap(modelObj: mymodelObj)
}

#SELEctor(someMethod)