swift – XCUITest应用程序快捷方式

或者,如果这是你唯一需要的东西,那就把它暴露出来：

@interface XCUIElement (PrivatE)
    - (void)forcePress;
@end

然后通过转到跳板并获取图标元素see my answer here来强制按下您的图标.

class Springboard {
    // this is another private method you'll need to expose (see linked other answer)
    static let springboard = XCUIApplication(privateWithPath: nil,bundlEID: "com.apple.springboard")


    /// Open the 3d touch menu
    class func open3dTouchMenu() {
        XCUIApplication().terminate() // this may or may not be necessary depending on your desired function / app state

        // Resolve the query for the springboard rather than launching it
        springboard.resolve()

        // Force delete the app from the springboard
        let icon = springboard.icons["MyAppName"]
        if icon.exists {
            icon.forcePress()
            // do something with the menu that comes up
        }
    }
 }

*我还没有测试过这个.