php – Symfony2服务容器 – 将普通参数传递给服务构造函数

我有这个Paginator类构造函数：

class Paginator
{    
    public function __construct($@R_805_10586@l_count,$per_page,$current_pagE)
    {
    }
}

Paginator服务在Ibw / JobeetBundle / resources / config / services.yml中注册,如下所示：

parameters:
    ibw_jobeet_paginator.class: Ibw\JobeetBundle\Utils\Paginator

services:
    ibw_jobeet_paginator:
        class: %ibw_jobeet_paginator.class%

当我像这样使用Paginator时：

$em = $this->getDoctrine()->getManager();

$@R_805_10586@l_jobs = $em->getRepository('IbwJobeetBundle:Job')->getJobsCount($id);
$per_page = $this->container->getParameter('max_jobs_on_category');
$current_page = $page; 

$paginator = $this->get('ibw_jobeet_paginator')->call($@R_805_10586@l_jobs,$current_pagE);

我得到这个例外：

我猜在向Paginator服务构造函数传递参数时出现了问题.你能告诉我,如何将参数传递给服务构造函数？

services:
    ibw_jobeet_paginator:
        class: %ibw_jobeet_paginator.class%
    arguments:
        - 1 # @R_805_10586@l
        - 2 # per page
        - 3 # current page

class Paginator
{    
    public function __construct() {}

    public function init($@R_805_10586@l_count,$current_pagE)
    {
    }
}

$paginator = $this->get('ibw_jobeet_paginator')->init($@R_805_10586@l_jobs,$current_pagE);