php – mysqli bind_param给出错误：(1210)mysql_stmt_execute的参数不正确

$MysqLi_Cxn = new MysqLi($sql_HOST,$sql_USER,$sql_PASS,$sql_DB);
if($MysqLi_Cxn->connect_errno){
echo 'Unable to connect!!';
exit();
}

$userID=12345;
$userFirstName = 'Charley';
$userLocale = 'en_US';

$sql = "updatE userProfile SET userFirstName=?,userLocale=? WHERE id=?";

if($stmt = $MysqLi_Cxn->prepare($sql)){
 if(!$stmt->bind_param('ssi',$userFirstName,$userLocale,$userID)){
  echo "<br/><br/>Binding parameters Failed: (" . $stmt->errno . ") " . $stmt->error;
 }
 if($stmt->execute()){
  @R_687_10586@lAffected=$stmt->affected_rows;
  if($@R_687_10586@lAffected>=1){
   echo '<br/><br/>updatE OK: Affected rows = '. $@R_687_10586@lAffected;
  }
 }else{
  echo "Execute Failed: (" . $stmt->errno . ") " . $stmt->error;
 }
}
$stmt->close();

该代码给出以下输出：
执行失败：(1210)不正确的参数到MysqL_stmt_execute

如果我改变这两行：

$sql = "updatE userProfile SET userFirstName=?,userLocale=? WHERE id=?";
$stmt->bind_param('ssi',$userID);

到这个：

$sql = "updatE userProfile SET userFirstName=?,userLocale='en_US' WHERE id=12345";
$stmt->bind_param('s',$userFirstName);

…然后更新成功,我没有收到任何错误.

有人知道为什么我不能绑定多个param在这段代码？

我的代码在Centos 4.9,PHP 5.3.3,MysqL 5.0.91 / 5.0.91-community-log上完美运行

我需要在我当前的服务器上运行它,这是Centos 6.2,PHP 5.3.10,MysqL 5.0.95-community-log