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PHP 发布时间：2022-04-09 发布网站：大佬教程 code.js-code.com

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我有这个数组：

$opening_hours = array(
  'Monday' => array('09:00','17:00'),'Tuesday' => array('09:00','Wednesday' => array('08:00','13:00'),'Thursday' => array('09:00','Friday' => array('09:00','Saturday' => array('10:00','16:00'),'Sunday' => array('Closed'),);

我需要以某种方式将这些开放时间合并到数组中,这应该是这样的：

$merged_opening_hours = array(
  'Monday - Tuesday' => array('09:00','Thursday - Friday' => array('09:00','16:00');
  'Sunday' => array('Closed'),);

有任何想法吗？

这应该适合你：

所以基本上你只需循环遍历整个数组并检查下一个元素是否仍然设置并且当前数组与下一个元素相同(这意味着它们具有相同的小时数).如果是,则执行此操作,直到while循环返回false.这是什么代码：

$DayamountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayamountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayamountOfConsecutiveSameHours)]]))
    $DayamountOfConsecutiveSameHours++;

然后,如果您有多个条目,则创建从一个到另一天的范围.这是什么代码：

if($DayamountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayamountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

如果您只有相同时间的1天,则只需将其添加到结果数组中.这是什么代码：

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

根据你在同一时间内跳过下一个数组元素的天数.这是什么代码：

$dayCount += ($DayamountOfConsecutiveSameHours - 1);

完整代码：

<?PHP

    $opening_hours = [
            "Monday" => ["09:00","17:00"],"Tuesday" => ["09:00","Wednesday" => ["08:00","13:00"],"Thursday" => ["09:00","Friday" => ["09:00","Saturday" => ["10:00","16:00"],"Sunday" => ["Closed"],];


    $amountOfDays = count($opening_hours);
    $arrayKeys = array_keys($opening_hours);

    for($dayCount = 0; $dayCount < $amountOfDays; $dayCount++) {
        $DayamountOfConsecutiveSameHours = 1;
        while(isset($arrayKeys[($dayCount+$DayamountOfConsecutiveSameHours)]) && ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayamountOfConsecutiveSameHours)]]))
            $DayamountOfConsecutiveSameHours++;

        if($DayamountOfConsecutiveSameHours > 1)
            $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayamountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];
        else
            $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

        $dayCount += ($DayamountOfConsecutiveSameHours - 1);
    }

    print_r($result);

?>

输出：

Array
(
    [Monday - Tuesday] => Array
        (
            [0] => 09:00
            [1] => 17:00
        )

    [Wednesday] => Array
        (
            [0] => 08:00
            [1] => 13:00
        )

    [Thursday - Friday] => Array
        (
            [0] => 09:00
            [1] => 17:00
        )

    [Saturday] => Array
        (
            [0] => 10:00
            [1] => 16:00
        )

    [Sunday] => Array
        (
            [0] => Closed
        )

)

Demo