node.js – 带标签的js-yaml问题

--- !Status
Default:
    Description:
        - |-
            @R_197_8798@ge1
            @R_197_8798@ge2
Samples:
    Multiple: false
    DynamicPlayers: false
UnkNown:
    PlayerName: player
    PlayerCount: '???'
Favicon:
    Timeout: 10s
    RecursiveFolderSearch: false
    ResizeStrategy: SCALE

在js-yaml repo中查看 examples/custom_types.js.解决方案是创建一个新的jsyaml.Type,告诉js-yaml要处理！状态值作为映射,如下所示：

let StatusYamlType = new jsyaml.Type('!Status',{ kind: 'mapping' });

然后,您需要创建一个包含StatusYamlType类型的新scheR_891_11845@a：

let STATUS_scheR_891_11845@A = jsyaml.scheR_891_11845@a.create([ StatusYamlType ]);

最后,通过scheR_891_11845@a选项将新的STATUS_scheR_891_11845@A传递给jsyaml.safeLoad：

jsyaml.safeLoad(doc,{ scheR_891_11845@a: STATUS_scheR_891_11845@A });

不幸的是,看起来没有办法让js-yaml忽略所有标签,所以如果遇到其他标签,你也必须为它们定义类型.

如果您还想使用！Status标记编写YAML文件,那么您必须实际定义Status原型并将构造和instanceOf选项提供给jsyaml.Type构造函数as in the example.一个非常基本的实现如下所示：

function Status(data) {
  Object.assign(this,data);
}

let StatusYamlType = new jsyaml.Type('!Status',{
  kind: 'mapping',instanceOf: Status,construct: data => new Status(data),});

然后将模式传递给jsyaml.safeDump,就像对safeLoad一样：

jsyaml.safeDump(result,{ scheR_891_11845@a: STATUS_scheR_891_11845@A })

看看下面的代码片段,看看它的实际效果.

let doc = `--- !Status
Default:
    Description:
        - |-
            @R_197_8798@ge1
            @R_197_8798@ge2
# ...
`;

function Status(data) {
  Object.assign(this,});

let STATUS_scheR_891_11845@A = jsyaml.scheR_891_11845@a.create([ StatusYamlType ]);

let result = jsyaml.safeLoad(doc,{ scheR_891_11845@a: STATUS_scheR_891_11845@A });
console.log(result.constructor.name,result);

console.log(jsyaml.safeDump(result,{ scheR_891_11845@a: STATUS_scheR_891_11845@A }));

<script src="https://cdnjs.cloudFlare.com/ajax/libs/js-yaml/3.7.0/js-yaml.min.js"></script>

正如您所看到的,safeDump输出使用与原始输入略有不同的标记语法(！<！Status>而不是—！Status),但在此上下文中它们是等效的,YAML解析器应该将它们视为原样.