node.js – 在同一文件中定义的Sinon stubbing helper方法

export function foo(id: number): Promise<Boolean> {
  return new Promise<Boolean>((resolve,reject) => {
    findSomething(id)
    .then((data) => {
      //do something with data
    })
  }
}

export function findSomething(id: number): Promise<Object> {
  return new Promise<Object> ((resolve,reject) => {
    let query = 'SELECT * FROM user';
    db.executeQuery(query);
    .then(data) => {
      if(data.length < 1) { reject(new Error('whoops')); }
      resolve(data);
    },(err) => {
      reject(err);
    })
  })
}

所以我正在使用Sinon为外部函数foo编写单元测试,因此我想将它调用的函数存根,findSomething.我这样做如下：

import * as @R_262_9004@db from '../../src/user-database';

describe('POST /someEndpoint',() => {
  describe('when successful',() => {
    let stub;

    beforeEach(function() {
      stub = sinon.stub(@R_262_9004@db,'findSomething');
    });

    afterEach(function() {
      stub.restore();
    }); 

    it('should respond with 200',function(donE) {
      stub.returns(anObjectIPredefine);

      request(server)
        .post(basePath)
        .send(aPayloadIPredefine)
        .expect(200,donE);
    });
  }
}

当我运行测试时,我没有看到我告诉存根的对象返回此stub.returns(anObjectIPredefine).实际上我将函数findSomething正常执行并从dB中获取数据.有什么明显的我做错了吗？我唯一的猜测是stub = sinon.stub(@R_262_9004@db,’findSomething’)不是用于在与被测试函数相同的范围内定义函数的正确语法.我无法找到替代语法.