javascript – jQuery .prop()返回undefined,而.attr()按预期工作 – 数据 – *

<div class="formRow">
    <label for="firstName">First name</label>
    <div class="detailsControlBtns">
        <button id="editFirstName" class="btn ctaBtn greenBtn editBtn">Edit</button>
        <button class="btn ctaBtn greenBtn saveBtn" data-detail="firstName">Save</button>
        <button id="closeFirstName" class="btn ctaBtn greyBtn closeBtn">Close</button>
    </div>
    <input type="text" id="firstName" name="firstName" value="[+firstName+]" readonly>
</div>

$(".saveBtn").on("click",function() {
    var saveBtn = $(this);
    // The following statement yields undefined. When using .attr() it works as expected.
    var detail = saveBtn.prop("data-detail");
    var relevanTinput = saveBtn.parent().next();
    // The following statement works as expected.
    var value = relevanTinput.prop("value");
    // ...
});

那是因为HTML元素上没有data-detail属性.

以下是.data(),.prop()和.attr()的快速说明：
DOM元素是一个对象,它具有方法和属性(来自DOM)和属性(来自呈现的HTML).其中一些属性通过属性id-> id,class-> className,title-> title,style-> style等获得其初始值.
考虑这个元素：< input type =“checkBox”checked data-detail =“somedata”>
以下结果将是：

$('input').prop('id'); // => " "-empty String,property id exist on the element (defined by DOM),but is not set.
$('input').attr('id');// => undefined - doesn't exist.

如果您执行以下操作：

$('input').attr('id',"somEID");
$('input').prop('id'); // =>  "somEID"
$('input').attr('id'); // =>  "somEID"

并且：

$('input').prop('id',"someOtherID");
$('input').prop('id');// =>  "someOtherID"
$('input').attr('id');// =>  "someOtherID"

请考虑以下因素：< input type =“text”data-detail =“somedata”value =“someValue”>

$('input').prop('value'); // =>  "someValue"
$('input').val();         // =>  "someValue"
$('input').attr('value'); // =>  "someValue"

如果你这样做：

$('input').prop('value','newVal');

// or

$('input').val('newVal');

$('input').prop('value'); // => "newVal"    -value of the property
$('input').val();         // => "newVal"    -value of the property
$('input').attr('value'); // => "someValue" -value of the attr didn't change,since in this case it is not 1:1 mapping (change of the prop value doesn't reflect to the attribute value).

案例与.data()

1)如何获得：

– 请记住,属性名称是data- *,属性名称是数据集,因此：

<input type="checkBox" data-detail="somedata" >

$('input')[0].dataset; //=> [object DOMStringMap] { detail: "somedata"}
 $('input')[0].dataset.detail; // => "somedata"
 $('input').prop('dataset'); //=>[object DOMStringMap] { detail: "somedata"}
 $('input').prop('dataset').detail; // => "somedata"
 $('input').data('detail'); // => "somedata"
 $('input').attr('data-detail');  //  => "somedata"

2)如何设置：

I)$(‘input’).prop(‘dataset’).detail =’newData’;

$('input').prop('dataset');  //=> [object DOMStringMap] { detail: "newData"}
 $('input').prop('dataset').detail; // => "newData"
 $('input').attr('data-detail'); // => "newData"
 $('input').data('detail'); // => "newData"

II)$(‘input’).attr(‘data-detail’,’newData’);

$('input').prop('dataset');  //=> [object DOMStringMap] { detail: "newData"}
 $('input').prop('dataset').detail; // => "newData"
 $('input').attr('data-detail'); // => "newData"
 $('input').data('detail'); // => "newData"

但检查第三种方式：

III)$(‘input’).data(‘detail’,’newData’);

$('input').prop('dataset'); // =>  [object DOMStringMap] { detail: "somedata"}
 $('input').prop('dataset').detail; // => "somedata"
 $('input').attr('data-detail'); // => "somedata"
 $('input').data('detail');  // => "newData"    <-----******

那么,这里发生了什么？

因此,为了获取数据 – * .data()永远不会出错：

$(".saveBtn").on("click",function() {
    var saveBtn = $(this);
    var detail = saveBtn.data("detail");
    var relevanTinput = saveBtn.parent().next();
    var value = relevanTinput.prop("value");

});