使用jquery忽略JSON调用中的部分键

我目前用json填充一些元素.但是如果加载了新的json. json看起来略有不同.如何忽略密钥的第一部分以使其有效.我以为我可以使用星号,但这给了我一个萤火虫的错误.

这是我的jQuery

var items = [];
    $.each(data[0].attributes['*.dyn.prop.current.profile'],function (key,val) {
        items.push(val);
    });
    displaySortLabel(items,"type-details");

示例JSON 1

[
   {
    "avatarDeFinitionId":1,"avatarName":"edge","attributes":{
       "examplePrefixToSkipOver.act.halt":"1","examplePrefixToSkipOver.dyn.prop.current.profile":"1","examplePrefixToSkipOver.dyn.prop.firmware":"1.0","examplePrefixToSkipOver.dyn.prop.ip.address.3g":"192.168.1.1","examplePrefixToSkipOver.dyn.prop.ip.address.cloud.com":"192.168.1.1","examplePrefixToSkipOver.dyn.prop.ip.address.lan":"10.0.0.1","examplePrefixToSkipOver.dyn.prop.ip.address.wifi":"192.168.1.1","examplePrefixToSkipOver.dyn.prop.LOCATIOn":"Chicago Office","examplePrefixToSkipOver.dyn.prop.name":"examplePrefixToSkipOver","examplePrefixToSkipOver.dyn.prop.priority":"1","examplePrefixToSkipOver.dyn.prop.status.detail":"Placeholder-Text","examplePrefixToSkipOver.dyn.prop.timestamp":"2010-01-01T12:00:00Z"

   }
 }
 ]

for ( key in data[0].attributes ) {
    if (key.match('.dyn.prop.firmware')) {
       items.push(data[0].attributes[key]);
    }
}