如何在jquery中循环遍历具有不同id的所有标记？

id="id_lines-0-label"
id="id_lines-0-description"
id="id_lines-1-label" 
id="id_lines-1-description"
id="id_lines-2-label"
id="id_lines-2-description"
id="id_lines-3-label"
id="id_lines-3-description
# and so on.

您可以使用子字符串选择器来获取具有给定子字符串的所有元素.举个例子,假设我们有一个带有那些id的div,那么你可以使用div [id * =’id_lines-‘]选择器来获取具有该模式的所有元素：

$(document).ready(function(){
  $( "div[id*='id_lines-']" ).each(function(indeX){
    var id = $(this).attr('id');
    //SELEct only label with id that has label text in its id
    if(id.indexOf('-label') !== -1){
      $(this).html('This is SELEcted label id = '+id);
    }
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="#id_lines-0-label"></div>
<div id="#id_lines-0-description"></div>
<div id="#id_lines-2-label"></div>
<div id="#id_lines-3-description"></div>
<div id="#id_lines-3-label"></div>
<div id="#id_lines-3-description"></div>
<div id="#id_lines-3-label"></div>