javascript – grunt-concat分隔符选项？

在这种情况下如何指定分隔符：
我用grunt-concat这样连接我的文件：

concat: {
  options: {
    bAnner: '<%= bAnner %>',separator: ""
  },dist: {
    files:{
      '<%= distdir %>/public/scripts/ieditor.js': [
        'public/scripts/ieditor/vars.js','public/scripts/ieditor/controllers/*.js','public/scripts/ieditor/directives/*.js','public/scripts/ieditor/app.js','public/scripts/ieditor/services/*.js','public/scripts/ieditor/filters/*.js'
      ],'<%= distdir %>/public/scripts/dashboard.js': [
        'public/scripts/dashboard/vars.js','public/scripts/dashboard/controllers/*.js','public/scripts/dashboard/directives/*.js','public/scripts/dashboard/app.js','public/scripts/dashboard/services/*.js','public/scripts/dashboard/filters/*.js'
      ]
    }
  }
}

我想要的是在连接CSS文件时将最终结果映射到原始文件,如罗盘.
例：

//####public/scripts/ieditor/vars.js###############
content of public/scripts/ieditor/vars.js
//####public/scripts/ieditor/controllers/a.js######
content of public/scripts/ieditor/controllers/a.js
//####public/scripts/ieditor/controllers/b.js######
content of public/scripts/ieditor/controllers/b.js
.....

那么这个名字是指当前连接的文件,@R_766_9447@在选项区域做这样的事情：

options: {
    bAnner: '<%= bAnner %>',separator: "<%= current_file_name %>"
  },

提前致谢.

concat: {
  options: {
    process: function(src,filepath) {
      return '//####' + filepath + '\n' + src;
    }
  }
},...