ios – Swift：捕获逃脱被调用函数的闭包中的inout参数

我试着编写一个“编辑器”类,它可以保留对不同对象上的属性的引用,以便以后进行突变.我首先编写了编辑器类来接收一个用于读取的闭包,以及一个用于写入的闭包.这很有效.然后我尝试通过(inout)引用传递有问题的参数,然后从中生成getter / setter对.这没用. Swift文档确实说(释义) Swift确定何时复制,何时不复制.我认为我反对这种限制的不可预测性,但我认为我提出的问题是一样的.

或者,是否可以为个人吸气剂和定位器获得咖喱功能？

我的代码是：

class SomeModel : Printable {

    var a:string

    init(a:string) {
        self.a = a
    }

    var description:string {
        return "\(self.a)"
    }
}


class Editor {

    var getter:()-> String
    var setter:(String)->()

    init(getter:()-> String,setter:(String)->()) {
        self.getter = getter
        self.setter = setter
    }

    convenience init(inout bindTo:string) {
        self.init(
            getter:{ return bindTo },setter: { v in bindTo = v })
    }

    func read() -> String {
        return self.getter()
    }

    func write(value:string) {
        self.setter(value)
    }
}


func TESTBindTo() {
    var readModel =  SomeModel(a:"Did not capture by reference");
    var bindForReading = Editor(bindTo: &readModel.a)
    readModel.a = "captured by reference!"
    println(bindForReading.read())

    var writeModel =  SomeModel(a:"Did not capture by reference");
    var bindForWriTing = Editor(bindTo: &writeModel.a)
    bindForWriTing.write("captured by reference")
    println(writeModel)
}

TESTBindTo()


func testExplicitGetterSetter() {

    var readModel =  SomeModel(a:"Did not capture by reference");
    var bindForReading = Editor(
        getter: { readModel.a },setter: { v in readModel.a = v })
    readModel.a = "captured by reference!"
    println(bindForReading.read())

    var writeModel =  SomeModel(a:"Did not capture by reference");
    var bindForWriTing = Editor(
        getter: { writeModel.a },setter: { v in writeModel.a = v })
    bindForWriTing.write("captured by reference")
    println(writeModel)     
}

testExplicitGetterSetter()

结果是：

Did not capture by reference
Did not capture by reference
captured by reference!
captured by reference

谢谢！