ios – 使用prepareForSegue Swift传递对象

override func prepareForSegue(segue: UIStoryboardSegue,sender: AnyObject?) {
        // Get the new view controller using [segue desTinationViewController].
        var nextScene =  segue.desTinationViewController as! VehicleDetailsTableViewController

        // Pass the SELEcted object to the new view controller.
        if let indexPath = self.tableView.indexPathForSELEctedRow() {
            let SELEctedVehicle = vehicles[indexPath.row]
            nextScene.currentVehicle = SELEctedVehicle
        }
    }

你必须在故事板中给出一个标识符(说mySeguE)

使用XCode 7,swift 2.x

override func prepareForSegue(segue: UIStoryboardSegue,sender: AnyObject?){....}

被调用为所有segues被称为形式您当前的UIViewController.所以识别者是区分不同的段落

然后使用这段代码：

override func prepareForSegue(segue: UIStoryboardSegue,sender: AnyObject?) {
    if segue.identifier == "mySegue" {
    var nextScene =  segue.desTinationViewController as! VehicleDetailsTableViewController

    // Pass the SELEcted object to the new view controller.
    if let indexPath = self.tableView.indexPathForSELEctedRow {
        let SELEctedVehicle = vehicles[indexPath.row]
        nextScene.currentVehicle = SELEctedVehicle
    }
  }
}

使用Xcode 8,swift 3.x

override func prepare(for segue: UIStoryboardSegue,sender: Any?) {
    if segue.identifier == "mySegue",let nextScene = segue.desTination as? VehicleDetailsTableViewController,let indexPath = self.tableView.indexPathForSELEctedRow {
        let SELEctedVehicle = vehicles[indexPath.row]
        nextScene.currentVehicle = SELEctedVehicle
    }
}

在NextScene之后放置一个断点,看看它是否在单击TableView中的任何单元格时被触发.如果不是,则故事板中提供的标识符名称必须与此处给出的不同.