大佬教程收集整理的这篇文章主要介绍了ios – if-let语句不解包可选,大佬教程大佬觉得挺不错的,现在分享给大家,也给大家做个参考。
if let tabBarController = topViewController as? UITabBarController { for subcontroller in tabBarController.viewControllers! { println(subcontroller.view) if let subcontrollerView = subcontroller.view { println(subcontrollerView) println(subcontrollerView!) if subcontrollerView!.window != nil && subcontroller.isViewLoaded() { topViewController = subcontroller as? UIViewController break; } } } }@H_696_4@据我所知,if-let语句应该为我解开条件 – 但这不是这里展示的行为.除非我再次打开可选项,否则我无法访问subcontrollerView的window属性. x-code控制台返回以下内容:
Optional(<UILayoutContainerView: 0x7fbccd44e7f0; frame = (0 0; 320 568); autoresize = W+H; gestureRecognizers = <NSArray: 0x7fbccacdde90>; layer = <CALayer: 0x7fbccd440e30>>) Optional(<UILayoutContainerView: 0x7fbccd44e7f0; frame = (0 0; 320 568); autoresize = W+H; gestureRecognizers = <NSArray: 0x7fbccacdde90>; layer = <CALayer: 0x7fbccd440e30>>) <UILayoutContainerView: 0x7fbccd44e7f0; frame = (0 0; 320 568); autoresize = W+H; gestureRecognizers = <NSArray: 0x7fbccacdde90>; layer = <CALayer: 0x7fbccd440e30>>@H_696_4@展开的可选和if-let常量是相同的.为什么?
for subcontroller in tabBarController.viewControllers! {@H_696_4@你要这个:
if let viewControllers = tabBarController.viewControllers as? [UIViewController] { for subcontroller in viewControllers {@H_696_4@所以完整的代码是这样的:
if let tabBarController = topViewController as? UITabBarController { if let viewControllers = tabBarController.viewControllers as? [UIViewController] { for subcontroller in viewControllers { if let subcontrollerView = subcontroller.view { if subcontrollerView.window != nil && subcontroller.isViewLoaded() { topViewController = subcontroller break; } } } } }@H_696_4@但我们可以做得更好.首先,可选链接通常是管理多个if-lets的更好方法,当它不能正常工作时,我们可以使用Swift 1.2的新的multi-if-let语法来实现:
if let tabBarController = topViewController as? UITabBarController,viewControllers = tabBarController.viewControllers as? [UIViewController] { for subcontroller in viewControllers { if subcontroller.view?.window != nil && subcontroller.isViewLoaded() { topViewController = subcontroller break; } } }
以上是大佬教程为你收集整理的ios – if-let语句不解包可选全部内容,希望文章能够帮你解决ios – if-let语句不解包可选所遇到的程序开发问题。
如果觉得大佬教程网站内容还不错,欢迎将大佬教程推荐给程序员好友。
本图文内容来源于网友网络收集整理提供,作为学习参考使用,版权属于原作者。
如您有任何意见或建议可联系处理。小编QQ:384754419,请注明来意。