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HTML5 发布时间：2022-04-27 发布网站：大佬教程 code.js-code.com

大佬教程收集整理的这篇文章主要介绍了iOS – 将图像发送到Instagram – DocumentInteraction，大佬教程大佬觉得挺不错的，现在分享给大家，也给大家做个参考。

是否可以绕过行动共享表将照片分享给Instagram？

请注意,我知道UIDocumenTinteractionController和钩子,事实上它工作正常.使用他们的示例代码,您可以获得Copy to Instagram选项(如果您使用独家UTI或可以处理JPG / PNG的大型应用程序列表,以及Instagram,则可以是唯一的).

这很好,但我想知道是否有办法执行“复制到Instagram”操作,而无需在iOS 9中显示UIDocumenTinteractionController菜单.

为了记录,这是完美运行的代码的简化版本.假设你有一个有效的NSURL ……

guard let data: NSData = NSData(contentsOfURL: url),image = UIImage(data: data) else {
            return
        }

        let imageData = UIImageJPEGRepresentation(image,100)
        let captionString = "caption"
        let writePath = (NstemporaryDirectory() as NSString).StringByAppendingPathComponent("instagram.ig")

        guard let _ = imageData?.writeToFile(writePath,atomically: truE) else {
            return
        }

        let fileURL = NSURL(fileURLWithPath: writePath)
        self.documentController = UIDocumenTinteractionController(URL: fileURL)
        self.documentController.delegate = self
        self.documentController.UTI = "com.instagram.photo"
        self.documentController.Annotation = NSDictionary(object: captionString,forKey: "InstagramCaption")
        self.documentController.presentOpenInMenuFromRect(viewController.view.frame,inView: viewController.view,animated: truE)

问题是,这将提供一个“操作表”,我想避免这样做,如果可能的话,我想使用instagram.ige(或任何名称使其独占)并跳过此ActionSheet.

那可能吗？

更新：我还没有找到解决方案,但似乎Instagram最终@L_607_10@/@L_607_10@扩展：“Instagram最近为其iOS应用程序@L_607_10@了共享扩展功能.现在,您可以直接将第三方应用程序的照片分享到Instagram”
来源：http://www.macworld.com/article/3080038/data-center-cloud/new-instagram-feature-for-ios-makes-it-easier-to-share-photos-from-other-apps.html

解决方法

import Photos
...

func postImageToInstagram(image: UIImagE) {
        UIImageWriteToSavedPhotosAlbum(image,self,#SELEctor(SocialShare.image(_:didFinishSavingWithError:co@R_616_10443@Tinfo:)),nil)
}
func image(image: UIImage,didFinishSavingWithError error: NSError?,co@R_616_10443@Tinfo:UnsafePointer<Void>) {
        if error != nil {
            print(error)
        }

        let fetchOptions = PHFetchOptions()
        fetchOptions.sortDescriptors = [NSSortDescriptor(key: "creationDate",ascending: falsE)]
        let fetchResult = PHAsset.fetchAssetsWithMediaType(.Image,options: fetchOptions)
        if let lastAsset = fetchResult.firstObject as? PHAsset {
            let localIdentifier = lastAsset.localIdentifier
            let u = "instagram://library?LocalIdentifier=" + localIdentifier
            let url = NSURL(String: u)!
            if UIApplication.sharedApplication().canOpenURL(url) {
                UIApplication.sharedApplication().openURL(NSURL(String: u)!)
            } else {
                let alertController = UIAlertController(title: "Error",message: "Instagram is not installed",preferredStyle: .Alert)
                alertController.addAction(UIAlertAction(title: "OK",style: .Default,handler: nil))
                self.presentViewController(alertController,animated: true,completion: nil)
            }

        }
}