ios – 使用选择器和NSSelectorFromString将消息发送到对象

以下将传递respondsToSELEctor测试,但SIGABRT实际调用[viewController选择器]或[viewController action：SELEctor].堆栈跟踪状态’NSInvalidArgume@R_618_10443@ception,原因： – [MyViewController选择器]：无法识别的选择器’.

[viewController @SELEctor(SELEctor)]将导致编译错误(错误：在’SELEctor’之前预期’：’).

当选择器是硬编码时,一切都很好.

如何通过选择器向对象发送消息？

-(void) notifyViewControllers:(NSString*) message
{
    if(!messagE) return;

    SEL SELEctor = NSSELEctorFromString(messagE);
    if(!SELEctor) return;

    NSArray* viewControllers = [self.tabBarController viewControllers];
    if(!viewControllers) return;

    for (UIViewController* viewController in viewControllers)
    {
        if(!viewController) conTinue;

        if ([viewController respondsToSELEctor:SELEctor]) {
            // [viewController SELEctor];
            [viewController action:SELEctor];
        }
    }
}

[self performSELEctor:@SELEctor(notifyViewControllers:) withObject: message];