ios – 如何在UITextView中显示可点击的链接

我试图在可点击链接的UITextview中显示一个归因的字符串.我创建了一个简单的测试项目,看看我在哪里错了,仍然无法弄清楚.我尝试启用用户交互并设置了shouldInteractWithURLs委托方法,但仍然无法使用.这是我的代码(对于只包含textview的视图控制器)

@IBOutlet weak var textView: UITextView!

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view,typically from a nib.
    let String = "Google"
    let linkString = NSMutableAttributedString(String: String)
    linkString.addAttribute(NSLinkAttributename,value: NSURL(String: "https://www.google.com")!,range: NsmakeRange(0,String.characters.count))
    linkString.addAttribute(NSFontAttributename,value: UIFont(name: "HelveticaNeue",size: 25.0)!,String.characters.count))
    textView.attributedText = linkString
    textView.delegate = self
    textView.SELEctable = true
    textView.userInteractionEnabled = true
}

这里是我实现的委托方法：

func textViewShouldBeginEdiTing(textView: UITextView) -> Bool {
    return false
}

func textView(textView: UITextView,shouldInteractWithURL URL: NSURL,inRange characterRange: NSRangE) -> Bool {
    return true
}

这还不行.我搜索了这个话题,没有任何帮助.非常感谢提前.