ios – UIGestureRecognizer和UITableViewCell问题

我附加一个UISwipeGestureRecognizer到一个UITableViewCell在cellForRowATindexPath：方法如下：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowATindexPath:(NSIndexPath *)indexPath {

    static NSString *CellIdentifier = @"Cell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell == nil) {
        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reusEIDentifier:CellIdentifier] autorelease];

        UISwipeGestureRecognizer *gesture = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@SELEctor(didSwipe:)];
        gesture.direction = UISwipeGestureRecognizerDirectionRight;
        [cell.contentView addGestureRecognizer:gesture];
        [gesture release];
    }
    return cell;
}

但是，didSwipe方法在成功滑动时总是调用两次。我最初认为这是因为手势开始和结束，但如果我退出手势识别器本身，他们都处于“已结束”状态：

-(void)didSwipe:(UIGestureRecognizer *)gestureRecognizer {

    NSLog(@"did swipe called %@",gestureRecognizer);
}

安慰：

2011-01-05 12:57:43.478 App[20752:207] did swipe called <UISwipeGestureRecognizer: 0x5982fa0; state = Ended; view = <UITableViewCellContentView 0x5982c30>; target= <(action=didSwipe:,target=<RootViewController 0x5e3e080>)>; direction = right>
2011-01-05 12:57:43.480 App[20752:207] did swipe called <UISwipeGestureRecognizer: 0x5982fa0; state = Ended; view = <UITableViewCellContentView 0x5982c30>; target= <(action=didSwipe:,target=<RootViewController 0x5e3e080>)>; direction = right>

我真的不知道为什么。我试图明显地检查结束状态，但这是没有帮助，因为他们都以“结束”反正…任何想法？

-(void)didSwipe:(UIGestureRecognizer *)gestureRecognizer {

  if (gestureRecognizer.state == UIGestureRecognizerStateEnded) {
        CGPoint swipeLOCATIOn = [gestureRecognizer LOCATIOnInView:self.tableView];
        NSIndexPath *swipedIndexPath = [self.tableView indexPathForRowAtPoint:swipeLOCATIOn];
        UITableViewCell* swipedCell = [self.tableView cellForRowATindexPath:swipedIndexPath];
        // ...
  }
}