大佬教程收集整理的这篇文章主要介绍了如何在Python中将datetime.timedelta转换为分钟和小时?,大佬教程大佬觉得挺不错的,现在分享给大家,也给大家做个参考。
没有用于timedelta
对象的内置格式化程序,但是你自己可以很容易地做到这一点:
days, seconds = duration.days, duration.seconds
hours = days * 24 + seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60
或者,等效地,如果你使用的是Python 2.7+或3.2+:
@H_262_6@seconds = duration.@R_778_10586@l_seconds()
hours = seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60
现在,你可以根据需要打印它:
@H_262_6@'{} minutes, {} hours'.format(minutes, hours)
例如:
@H_262_6@def convert_timedelta(duration):
days, seconds = duration.days, duration.seconds
hours = days * 24 + seconds // 3600
minutes = (seconds % 3600) // 60
seconds = (seconds % 60)
return hours, minutes, seconds
td = datetiR_181_11845@e.timedelta(2, 7743, 12345)
hours, minutes, seconds = convert_timedelta(td)
print '{} minutes, {} hours'.format(minutes, hours)
这将打印:
@H_262_6@9 minutes, 50 hours
如果要获取“ 10分钟1小时”而不是“ 10分钟1小时”,则也需要手动执行此操作:
@H_262_6@print '{} minute{}, {} hour{}'.format(minutes, 's' if minutes != 1 else '',
hours, 's' if minutes != 1 else '')
或者,你可能想编写一个english_plural函数’s’为你完成这些操作,而不是重复自己。
从你的评论看来,你实际上是想让日子分开。这甚至@R_801_11222@:
@H_262_6@def convert_timedelta(duration):
days, seconds = duration.days, duration.seconds
hours = seconds // 3600
minutes = (seconds % 3600) // 60
seconds = (seconds % 60)
return days, hours, minutes, seconds
如果要将其转换为单个值以存储在数据库中,然后将该单个值转换回以对其进行格式化,请执行以下操作:
@H_262_6@def dhms_to_seconds(days, hours, minutes, seconds):
return (((days * 24) + hours) * 60 + minutes) * 60 + seconds
def seconds_to_dhms(seconds):
days = seconds // (3600 * 24)
hours = (seconds // 3600) % 24
minutes = (seconds // 60) % 60
seconds = seconds % 60
return days, hours, minutes, seconds
因此,将其放在一起:
@H_262_6@def store_timedelta_in_database(thingy, duration):
seconds = dhms_to_seconds(*convert_timedelta(duration))
db.execute('INSERT INTO foo (thingy, duration) VALUES (?, ?)',
thingy, seconds)
db.commit()
def print_timedelta_from_database(thingy):
cur = db.execute('SELECT duration FROM foo WHERE thingy = ?', thingy)
seconds = int(cur.fetchone()[0])
days, hours, minutes, seconds = seconds_to_dhms(seconds)
print '{} took {} minutes, {} hours, {} days'.format(thingy, minutes, hours, days)
我得到这样的开始日期:
@H_262_6@from django.utils.timezone import utc
import datetiR_181_11845@e
start_date = datetiR_181_11845@e.datetiR_181_11845@e.utcnow().replace(tzinfo=utC)
END_DATE = datetiR_181_11845@e.datetiR_181_11845@e.utcnow().replace(tzinfo=utC)
duration = END_DATE - start_date
我得到这样的输出:
@H_262_6@datetiR_181_11845@e.timedelta(0,5,41038)
如何将其转换为正常时间,如下所示?
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