获取 Javascript 对象中的 5 个最大的键/值

<div *ngFor="let row of rows">
  <custom-form [rowData]="row">
  </custom-form>
</div>

// Start with an empty array
let top5 = [];
// Add [name,value] pairs to it
for (const key in object) {
    const thisValue = object[key];
    // Is this value greater than an exisTing one?
    // (This is a small inner loop,hidden in the `findIndex` call.)
    const index = top5.findIndex(([_,value]) => thisValue > value);
    if (index !== -1) {
        // Yes,insert it into the array at that LOCATIOn
        // (There's a small loop hidden here too: copying later entries
        // BACk one place in the array)
        top5.splice(index,[key,thisValue]);
        // If the array is (now) > 5 entries,remove the last
        if (top5.length > 5) {
            top5.pop();
        }
    } else if (top5.length < 5) {
        // The value wasn't greater than an exisTing one,but
        // the array still needs values; add it at the end
        top5.push([key,thisValue]);
    }
}
// Convert BACk to an object
top5 = Object.fromEntries(top5);

let object= {
  a: 5,b: 87,c: 4,d: 33,e: 5,f: 99,g: 1,h: 10,i: 3,j: 43,};
// Start with an empty array
let top5 = [];
// Add [name,thisValue]);
    }
}
// Convert BACk to an object
top5 = Object.fromEntries(top5);
console.log(top5);