大佬教程收集整理的这篇文章主要介绍了java-我可以在Android中使用POST方法从URL获取数据吗？ ，大佬教程大佬觉得挺不错的，现在分享给大家，也给大家做个参考。
我想使用POST方法从URL提取数据.我已经使用GET方法获取了数据.现在,我想使用POST方法.当我单击按钮时,即使我提供了Internet许可,也没有任何响应.我认为还有其他问题.
我曾尝试搜索许多站点并观看教程,但是我所获得的只是如何使用POST方法将数据发送到服务器.
@H_781_1@mainActivity.java
package com.example.apipostmethod;
import android.os.StrictMode;
import android.support.v7.app.AppCompatActivity;
import android.os.bundle;
import android.view.View;
import android.widget.button;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends AppCompatActivity {
public String data="";
public TextView response;
public Button btn;
@Override
protected void onCreate(Bundle savedInstanceStatE) {
super.onCreate(savedInstanceStatE);
setContentView(R.layout.activity_main);
if (android.os.build.VERSION.SDK_INT > 15) {
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
}
response = findViewById(R.id.textView);
btn = findViewById(R.id.button);
btn.setOnClickListener(new View.onClickListener() {
@Override
public void onClick(View v) {
new Async().execute();
}
});
data = Async.data();
Toast.makeText(getApplicationContext(),data,Toast.LENGTH_LONG).show();
response.setText(data);
}
}
异步.java
package com.example.apipostmethod;
import android.os.AsyncTask;
import java.io.IOException;
import java.net.httpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.ScAnner;
public class Async extends AsyncTask {
public String URLine = "https://api.myjson.com/bins/uizi7";
public static String result="";
@Override
protected Object doInBACkground(Object[] objects) {
try {
URL url = new URL(URLinE);
httpURLConnection httpURLConnection = (httpURLConnection)url.openConnection();
httpURLConnection.setrequestMethod("POST");
httpURLConnection.connect();
ScAnner sc = new ScAnner(url.openStream());
while(sc.hasNext())
{
result+=sc.nextLine();
}
}
catch (MalformedURLException E) {
e.printStackTrace();
} catch (IOException E) {
e.printStackTrace();
}
return null;
}
public static String data(){
return result;
}
}
activity_main.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://scheR_187_11845@as.android.com/apk/res/android"
xmlns:app="http://scheR_187_11845@as.android.com/apk/res-auto"
xmlns:tools="http://scheR_187_11845@as.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
tools:context="com.example.apipostmethod.MainActivity">
<Button
android:id="@+id/button"
android:layout_width="236dp"
android:layout_height="57dp"
android:layout_marginStart="8dp"
android:layout_marginLeft="8dp"
android:layout_marginTop="8dp"
android:layout_marginEnd="8dp"
android:layout_marginRight="8dp"
android:layout_marginBottom="8dp"
android:text="Button"
app:layout_consTraintBottom_toBottomOf="parent"
app:layout_consTraintEnd_toEndOf="parent"
app:layout_consTraintHorizontal_bias="0.496"
app:layout_consTraintStart_toStartOf="parent"
app:layout_consTraintTop_toTopOf="parent"
app:layout_consTraintVertical_bias="0.898" />
<TextView
android:id="@+id/textView"
android:layout_width="347dp"
android:layout_height="531dp"
android:layout_marginStart="8dp"
android:layout_marginLeft="8dp"
android:layout_marginEnd="8dp"
android:layout_marginRight="8dp"
android:layout_marginBottom="8dp"
android:text="Response::"
app:layout_consTraintBottom_toTopOf="@+id/button"
app:layout_consTraintEnd_toEndOf="parent"
app:layout_consTraintStart_toStartOf="parent"
app:layout_consTraintTop_toTopOf="parent" />
</LinearLayout>
我连续不断地在logcat中收到此错误,例如无限次.
2019-06-06 16:03:48.315 1930-2875/? I/GnssLOCATIOnProvider: WakeLock acquired by sendmessage(REPORT_SV_STATUS,com.android.server.LOCATIOn.GnssLOCATIOnProvider$SvStatusInfo@494d84f)
2019-06-06 16:03:48.316 1930-1944/? I/GnssLOCATIOnProvider: WakeLock released by handlemessage(REPORT_SV_STATUS,com.android.server.LOCATIOn.GnssLOCATIOnProvider$SvStatusInfo@494d84f)
我希望在textview中获取数据,但是我什至看不到用textview编写的文本.
URL url = new URL("http://yoururl.com");
httpsURLConnection conn = (httpsURLConnection) url.openConnection();
conn.setReadTimeout(7000);
conn.setConnectTimeout(10000);
conn.setrequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("param1",paramValue1));
params.add(new BasicNameValuePair("param2",paramValue2));
OutputStream outputStream = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(outputStream,"UTF-8"));
writer.write(getQuery(params));
writer.flush();
writer.close();
outputStream.close();
conn.connect();
这是getQuery()方法：
private String getQuery(List<NameValuePair> params) throws UnsupportedEncodingException
{
StringBuilder result = new StringBuilder();
Boolean first = true;
for (NameValuePair pair : params)
{
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(pair.getName(),"UTF-8"));
result.append("=");
result.append(URLEncoder.encode(pair.getValue(),"UTF-8"));
}
return result.toString();
}
以上是大佬教程为你收集整理的java-我可以在Android中使用POST方法从URL获取数据吗？ 全部内容，希望文章能够帮你解决java-我可以在Android中使用POST方法从URL获取数据吗？ 所遇到的程序开发问题。
如果觉得大佬教程网站内容还不错，欢迎将大佬教程推荐给程序员好友。
本图文内容来源于网友网络收集整理提供，作为学习参考使用，版权属于原作者。
如您有任何意见或建议可联系处理。小编QQ：384754419，请注明来意。