android – 如何在文件打包时用Gradle删除原始XML文件中的注释

我的项目在我的 Android项目的原始资源目录中有XML文件：

当我打包在.apk文件中时,我想从这些文件中删除评论(<！ - ... - >)：

原始文件样本：

<?xml version="1.0" encoding="utf-8"?>
    <celebrations xmlns:xsi="http://www.w3.org/2001/XMLscheR_549_11845@a-instance"
              xsi:noNamespacescheR_549_11845@aLOCATIOn="celebrations_scheR_549_11845@a.xsd">

    <!-- This is a very important comment useful during development -->
    <celebration name="celebration 1" type="oneTime" ... />

    <!-- This is another very important comment useful during development -->
    <celebration name="celebration 2" type="reccurent" ... />
</celebrations>

预期过滤文件：

<?xml version="1.0" encoding="utf-8"?>
<celebrations xmlns:xsi="http://www.w3.org/2001/XMLscheR_549_11845@a-instance"
              xsi:noNamespacescheR_549_11845@aLOCATIOn="celebrations_scheR_549_11845@a.xsd">
    <celebration name="celebration 1" type="oneTime" ... />
    <celebration name="celebration 2" type="reccurent" ... />
</celebrations>

我找到了一些有趣的类似解决方案@L_403_2@,但我无法管理它的工作.在我的应用程序build.gradle中添加这些行

processresources {
    filesmatching('**/myxmlfiletobeStrippedfromcomments.xml') {
        filter {
            String line -> line.replaceAll('<!--.*-->','')
        }
    }
}

会产生以下错误：

Error:(86,0) Gradle DSL method not found: 'processresources()'

对于从java代码打开和解析XML文件,我使用以下方法：

InputStream de@L_618_16@n = context.getresources().openRawresource(resId);
...
try {
    XmlPullParser parser = Xml.newPullParser();
    parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES,falsE);
    parser.seTinput(de@L_618_16@n,null);
    parser.nextTag();
    return parseCelebrations(parser);
} finally {
    de@L_618_16@n.close();
}