android – 让按钮打开浏览器到特定URL的最简单方法

这是一个我已经拥有的简单应用程序,我想要通过浏览器启动特定URL的按钮.你能不能给我一些信息来实现这一目标,就像我说我已经有了按钮已经进入我的应用程序.这是代码 – 知道你是否需要其他任何东西

.java文件

package reseeveBeta.mpi.dcasey;

import android.app.Activity;
import android.os.bundle;

public class ReseeveBetaActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceStatE) {
    super.onCreate(savedInstanceStatE);
    setContentView(R.layout.main);                
    }  

}

.XML

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://scheR_325_11845@as.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >

<TextView
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:text="Welcome to Reseeve,tap register to begin account creation" />

<Button
    android:id="@+id/button1"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:text="Register" />

<EditText
    android:id="@+id/editText1"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:ems="10"
    android:inputType="textMultiLine"
    android:text="If you already have and account,please login below" >

    <requestFocus />
</EditText>

</LinearLayout>

startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("http://www.google.com")));

//define class variables here
Button btn;

protected void onCreate(Bundle savedInstanceStatE)
{
    //some code of yours
    btn=(Button)findViewById(R.id.button1);
    btn.setOnClickListener(this);
    //more code of yours
}

//whatever else you have in your source code

public void onClick(View v)
{
    //handle the click events here,in this case open www.google.com with the default browser
    startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("http://www.google.com")));
}