数组 – 检查数组是否包含某些内容 – Swift 4

@H_696_1@

@H_618_4@ 我发现.contains(Element)方法在我编写 Swift代码的最小经验中非常重要,并且很快意识到Apple改变了它…

func contains(check:[[[Int]]],forElement: [[Int]]) -> Bool {
    for element in check {
        if areEqual(element,forElement) {
            return true
        }
    }
    return false
}
func areEqual(_ a:[[Int]],_ b:[[Int]]) -> Bool {
    for i in 0..<a.count {
        if a[i] != b[i] {
            return false
        }
    }
    return true
}

我一直在搞乱一些大型数组,所以我用那个笨重的函数解决了我的问题.

发生了什么？

你如何使用the new way？

那里的例子很好,我确信他们打算这样做.

enum httpResponse {
    case ok
    case error(int)
}

let lastThreeResponses: [httpResponse] = [.ok,.ok,.error(404)]
let hadError = lastThreeResponses.contains { element in
    if case .error = element {
        return true
    } else {
        return false
    }
}
// 'hadError' == true

let numbers = [1,2,3,4]
let contains = numbers.contains(where: { $0 == 3 })
//contains == true

let Strings = ["A","B","C","D"]
let contains = Strings.contains(where: { $0 == "B" })
//contains == true

let colors: [NSColor] = [.red,.blue,.green]
contains = colors.contains(where: { $0 == .red })
//contains == true