linux – Bash脚本的工作原理是提示,但不是来自cron

/bin/sh: -c: line 0: unexpected EOF while looking for matching ``'
/bin/sh: -c: line 1: Syntax error: unexpected end of file

奇怪的是,它在提示符下执行时效果很好

全剧本

#!/bin/sh
Now=$(date +"%b-%d-%y")
bu_PATH="/home/webserver/"

curtime=$(datE)

echo ""
echo "StarTing BACkup: $curtime"
echo ""
echo "Moving to $bu_PATH"
cd $bu_PATH

BACKUP_FILE="BACkup_$Now.tgz"

echo ""
echo "The BACkup file will be called $BACKUP_FILE"

RUN_BACKUP="/usr/local/psa/bin/pleskBACkup --server --output-file=$bu_PATH$BACKUP_FILE"

echo "Running BACkup...."
echo `$RUN_BACKUP`

curtime=$(datE)

echo "BACkup complete: $curtime"

echo ""

echo "Remove older than 7 days of files..."
ssh server '/shares/BACkup/webserver/cleanup.sh'

curtime=$(datE)
echo ""

echo "ConnecTing to FTP: $curtime"

sftp -b server <<EOF
        cd /shares/BACkup/webserver/
        put $bu_PATH$BACKUP_FILE
        quit
EOF;

curtime=$(datE)
echo "FTP Transfer Complete: $curtime"
echo ""
echo "Cleaning up Local BACkups"
sh /home/cleanup.sh
echo ""
echo "Clean up log files"
find /home/webserver/logs/*.log -mtime +7 -exec rm {} \;
echo "Job Complete"

这是crontab条目

/home/BACkup.sh > /home/webserver/logs/BACkupLog-`date +%m%d%y`.log

谢谢
抢