如何将Swift中的多参函数转化成Curring函数

假设我们有一个含有多个参数的函数，用于构建一个人的基本信息：

@H_801_16@func buildInfoWithName(name: String,#age: Int,#gender: String,#address: String,#phone: String) -> String { return "My name is " + name + ",I'm a " + gender + ",I live in " + address + ",my phone number is " + phone } let mike = buildInfoWithName("Mike",age: 20,gender: "boy",address: "Tokyo Japan",phone: "12345678")

如果我们不想一次性提供所有的参数，可以把它改造成Curring函数：

func buildInfoWithName(name: String)(age: int)(gender: String)(address: String)(phone: String) -> String {
    
    return "My name is " + name
    +  ",I'm a " + gender
    +  ",I live in " + address
    +  ",my phone number is " + phone
}

let benson = buildInfoWithName("Benson")(age: 24)(gender: "boy")(address: "Chengdu Sichuan")(phone: "87654321")

我们把原始的函数已经分解成了接受单一参数的函数序列。

参考链接：http://justtesTing.org/post/94325843216/what-is-currying-in-swift