大佬教程收集整理的这篇文章主要介绍了PHP登录脚本和SQL查询始终返回相同的用户ID，大佬教程大佬觉得挺不错的，现在分享给大家，也给大家做个参考。
我发布了一个问题,寻求帮助来解决我遇到的问题,由于已本地化,因此已关闭.我现在解决了我的问题.
我问的原始问题可以看到PHP Login Script Returning Same user id?.
基本上,当我登录时,从数据库中检索到的user_uid(用户uid)始终为3,由于某种原因,它没有获得正确的user_uid,但是存储在会话中的所有其他详细信息都是正确的.
引起问题的查询是这一
$stmt = $dbh->prepare("
SELECT
*
FROM
users, users_roles, users_profiles
WHERE
user_login = :username
OR
user_email = :email
LIMIT 1");
如果我从SQL查询中删除users_roles和users_profiles,而只是从users表中检索,它将获得正确的user_uid,这一定与我要从多个表中检索并且查询在某处混乱有关.
这是我的架构和SQL查询http://sqlfiddle.com/#!2/3cc32/1/0到sqlfiddle的链接
下面是回显的值数组,由于某种原因,即使以测试帐户PHPlover身份登录时user_uid假定为6,它也显示user_uid’3′(位于表的第一行)似乎在某处发生冲突.
经过进一步测试,似乎它从user表中获得了正确的数据,但user_uid除外,但是它从users_profiles和users_roles中检索了数据库第一行的信息,也许它是从users表中正确获取了user_uid,但是查询可能是覆盖它.
我运行的查询是@L_169_18@myAdmin,它仍然执行相同的操作,这绝对与我的SQL查询有关,如何解决我的查询,以便它检索正确的user_uid？
Array
(
[user_uid] => 3 // should be 6, 3 is the user_uid of the first row in database, seems to just fetch first row :/
[user_status] => 1
[user_login] => PHPLover
[user_pass] => 5e79a29e6292e7690a6bf56484140114f1374933081d499b8cc5034685950a16668868cd0886d93f9bc634a5649a6037022a5ef62e9b5d13cda24619bbdf610b;507a7ea891f609.84619944
[user_email] => smaple@sample.com
[user_registered] => 2012-10-14 09:58:16
[user_display_name] =>
[user_Failed_logins] => 0
[id] => 3 // not sure where this is coming from but should be 6 like user_uid
[user_role] => subscriber
[user_gender] =>
[user_url] =>
[user_R_697_11845@sn] =>
[user_aim] =>
[user_yim] =>
[user_twitter] =>
[user_facebook] =>
)
这是我的登录脚本,因为我将问题范围缩小到了SQL查询,因此无需显示它,但是我认为我会发布它,以防它帮助人们进一步了解正在发生的事情.
<?PHP
// ob_start()
ob_start();
// Include config.PHP
require_once("".$_SERVER['DOCUMENT_ROOT']."/de-admin/config.PHP");
// if user is logged in redirect them to control panel
// an already logged in user cAnnot login whilst already logged in!
alreadyloggedin();
// top.inc.PHP
require_once($top_inc);
?>
<!-- Meta start -->
<title><?PHP echo SITE_NAME; ?> - Member Login</title>
<Meta name="description" content="<?PHP echo SITE_NAME; ?> - Member Login, Sign in" />
<Meta name="keywords" content="sign up, member, login, signin, account, membership, <?PHP echo SITE_NAME; ?>" />
<!-- Meta end -->
<?PHP
// sidebar.inc.PHP
require_once($sidebar_inc);
// main.inc.PHP
require_once($main_inc);
?>
<?PHP
if(isset($_POST['username_email'], $_POST['password'], $_POST[BOT_TEST], $_POST['token'])){
// check if form token is valid
IsValidFormTokenHash();
// initialize form errors array
$error = array();
// fetch form data
$username_email = trim($_POST['username_email']);
$password = trim($_POST['password']);
$bottest = $_POST[BOT_TEST];
// validate form data
if(empty($username_email)){
$error[] = 'Please enter your username or email address';
}
if(empty($password)){
$error[] = 'Please enter your password';
}
if(!empty($bottest)){
$error[] = 'Spambot detected, if your human please try again';
}
if(!empty($username_email) && !empty($password)){
try{
// connect to database
$dbh = sql_con();
// prepare query
$stmt = $dbh->prepare("
SELECT
*
FROM
users, users_roles, users_profiles
WHERE
users.user_login = :username
OR
users.user_email = :email
AND
users.user_uid = users_roles.user_uid
AND
users.user_uid = users_profiles.user_uid
LIMIT 1");
// execute query
$stmt->execute(array(':username' => $username_email, ':email' => $username_email));
if ($stmt->rowCount() > 0) {
$result = $stmt->fetch(PDO::FETCH_ASSOC);
echo '<pre>';
print_r($result);
echo '</pre>';
$user_db_pass = $result['user_pass'];
if(!Validatepassword($password, $user_db_pass)){
$error[] = 'Invalid Login Details';
} else {
$user_status = $result['user_status'];
if($user_status == user_STATUS_VERIFY){
$error[] = 'You must verify your account before you can log in';
}elseif($user_status == user_STATUS_SUSPENDED){
$error[] = 'This account has been suspended';
}elseif($user_status == user_STATUS_SPAM){
$error[] = 'This account has been marked as potentially spam';
} else {
// user valid
// fetch user details and assign there details to there sessions
$_SESSION['user_uid'] = $result['user_uid'];
$_SESSION['user_status'] = $result['user_status'];
$_SESSION['user_login'] = $result['user_login'];
$_SESSION['user_email'] = $result['user_email'];
$_SESSION['user_registered'] = $result['user_registered'];
$_SESSION['user_display_name'] = $result['user_display_name'];
$_SESSION['user_role'] = $result['user_role'];
$_SESSION['user_gender'] = $result['user_gender'];
$_SESSION['user_url'] = $result['user_url'];
$_SESSION['user_R_697_11845@sn'] = $result['user_R_697_11845@sn'];
$_SESSION['user_aim'] = $result['user_aim'];
$_SESSION['user_yim'] = $result['user_yim'];
$_SESSION['user_twitter'] = $result['user_twitter'];
$_SESSION['user_facebook'] = $result['user_facebook'];
// unset (destroy) form token
UnsetFormToken();
// On successful login get URI user was on
// so we can redirect them BACk to URI they was on
/*if(isset($_SESSION['redirect_to'])){
// if session redirect_to is found this means
// they tried to access a membersarea()
// so we get the URI and redirect to the
// secure page they tried accessing before logged in
$redirect_to = $_SESSION['redirect_to'];
// unset the session var
unset($_SESSION['redirect_to']);
// redirect
header("LOCATIOn: ".SITE_URl."$redirect_to");
exit();
} else {
header("LOCATIOn: /member/control-panel");
exit();
}*/
// Now logged in redirect to control panel
//header("LOCATIOn: /member/control-panel");
exit;
}
}
} else {
$error[] = 'Incorrect login details';
}
// close database connection
$dbh = null;
}
catch (PDOException $E){
ExceptionErrorHandler($E);
require_once($footer_inc);
exit;
}
}
// If errors found display errors
if(!empty($error)){
$SiteErrormessages = '';
foreach($error as $msg){
$SiteErrormessages .= "$msg <br />";
}
}
}
// display error messages
if(isset($SiteErrormessages)){
SiteErrormessages();
}
// the below values is to replace placeholders in tpl
$TemplatereplacementValues = array(
'SITE_NAME' => SITE_NAME,
'FORM_TOKEN_HASH' => GenerateFormTokenHash(),
'BOT_TEST' => Bottest()
);
// signup.tpl template LOCATIOn
$tpl = DOCUMENT_ROOT.'inc/tPL/login.tpl';
// load signup template
PageContentTemplate($tpl, $TemplatereplacementValues);
?>
<?PHP
// footer.inc.PHP
require_once($footer_inc);
// ob_end-flush
ob_end_flush();
?>
解决方法:
改写这个：
FROM users, users_profiles, users_roles
对此：
FROM users
INNER JOIN users_profiles USING (user_uid)
INNER JOIN users_roles USING (user_uid)
…否则,您的查询会产生CROSS JOIN(至少可以这样说,效率非常低).
如果某些用户记录在users_profiles和users_roles中可能没有对应的记录,则应在此处用LEFT OUTER JOIN替换INNER JOIN(对于这些用户,在返回的行集中,对应的列值将设置为NULL).
以上是大佬教程为你收集整理的PHP登录脚本和SQL查询始终返回相同的用户ID全部内容，希望文章能够帮你解决PHP登录脚本和SQL查询始终返回相同的用户ID所遇到的程序开发问题。
如果觉得大佬教程网站内容还不错，欢迎将大佬教程推荐给程序员好友。
本图文内容来源于网友网络收集整理提供，作为学习参考使用，版权属于原作者。
如您有任何意见或建议可联系处理。小编QQ：384754419，请注明来意。