asp.net-mvc – 如何在ASP.NET MVC控制器中设置十进制分隔符？

我刚刚在一个真正的项目中重新审视了这个问题，最终找到了一个可行的解决方案。正确的解决方案是使用十进制类型的自定义模型绑定(如果使用十进制，则为十进制)：

public class decimalmodelBinder : DefaultModelBinder
{
    public override object BindModel(ControllerContext controllerContext,ModelBindingContext bindingContext)
    {
        object result = null;

        // Don't do this here!
        // It might do bindingContext.ModelState.AddModelError
        // and there is no RemoveModelError!
        // 
        // result = base.bindModel(controllerContext,bindingContext);

        String modelName = bindingContext.ModelName;
        String attemptedValue =
            bindingContext.ValueProvider.GetValue(modelName).AttemptedValue;

        // Depending on CultureInfo,the numberdecimalSeparator can be "," or "."
        // Both "." and "," should be accepted,but aren't.
        String wantedSeperator = numberFormaTinfo.CurrenTinfo.numberdecimalSeparator;
        String alternateSeperator = (wantedSeperator == "," ? "." : ",");

        if (attemptedValue.IndexOf(wantedSeperator) == -1
            && attemptedValue.IndexOf(alternateSeperator) != -1)
        {
            attemptedValue =
                attemptedValue.replace(alternateSeperator,wantedSeperator);
        }

        try
        {
            if (bindingContext.ModelMetadata.IsNullableValueType
                && String.IsNullOrWhiteSpace(attemptedvalue))
            {
                return null;
            }

            result = decimal.Parse(attemptedValue,numberStyles.Any);
        }
        catch (FormatException E)
        {
            bindingContext.ModelState.AddModelError(modelName,E);
        }

        return result;
    }
}

然后在Application.Start()中的Global.asax.cs中：

@H_226_8@modelBinders.binders.Add(typeof(decimal),new decimalmodelBinder()); ModelBinders.binders.Add(typeof(decimal?),new decimalmodelBinder());

请注意，代码不是我的，我实际上是在Kristof Neirynck的博客here中找到的。我刚刚编辑了几行，并添加了特定数据类型的binder，而不是替换默认的绑定。