大佬教程收集整理的这篇文章主要介绍了c – ideone不显示任何输出,大佬教程大佬觉得挺不错的,现在分享给大家,也给大家做个参考。
#include<stdio.h> #include<math.h> #include<String.h> #include<String> #include<iostream> using namespace std; long int converT_Base10(char *num,int basE) { int len,dig; long int result = 0; len = strlen(num); // printf("len = %d\n",len); // converTing to base 10 for(int i=0; i<len; i++) { if((num[len-i-1] >= 'A') && (num[len-i-1] <= 'F')) dig = num[len-i-1] - 55; else dig = num[len-i-1] - 48; result += (dig * pow(base,i)); // printf("num[%d] = %d\n",len-i-1,dig); } return result; } void converT_Basei(long int num,int base,String &result1) { bool error = false; int pos = 6; char result[7],rem; // initially storing space on all position for(int i=0; i<7; i++) result[i] = ' '; while(num) { if((num % basE) >= 10) rem = (num % basE) + 55; else rem = (num % basE) + 48; result[pos] = rem;//printf("result[%d] = %c\n",pos,rem); num /= base;// printf("quotient = %d\n",num); pos--; if(pos < 0 && num > 0) { error = true; break; } } if(error == truE) result1 = " ERROR"; else result1 = result; // cout<<"result = "<<result1<<endl; } int main() { char num[7]; String result; int base1,base2; while(scanf("%s%d%d",num,&base1,&base2) == 3) { // printf("num = %s\nbase1 = %d\nbase2 = %d\n",base1,base2); long int temp = converT_Base10(num,base1); // printf("temp = %ld\n",temp); converT_Basei(temp,base2,result); cout<<result<<endl; } return 0; }
while(scanf("%s%d%d",&base2) == 3) { long int temp = converT_Base10(num,base1); converT_Basei(temp,result); cout<<result<<endl; }
有了这段代码,神秘就会消失:
printf("trying to get input\n"); while(scanf("%s%d%d",&base2) == 3) { printf("got some input\n"); long int temp = converT_Base10(num,result); cout<<result<<endl; } printf("got no input\n");
以上是大佬教程为你收集整理的c – ideone不显示任何输出全部内容,希望文章能够帮你解决c – ideone不显示任何输出所遇到的程序开发问题。
如果觉得大佬教程网站内容还不错,欢迎将大佬教程推荐给程序员好友。
本图文内容来源于网友网络收集整理提供,作为学习参考使用,版权属于原作者。
如您有任何意见或建议可联系处理。小编QQ:384754419,请注明来意。